Electric power in watts (W) to illuminance in lux (lx) calculator and how to calculate.

Enter the power in watts, luminous efficacy in lumens per watt, surface area in square feet / meters or spherical radius in feet / meters and press the *Calculate* button to get the illuminance in lux:

* the predefined luminous efficacy values are typical / average values.

So The luminous flux *Φ*_{V} in lumens (lm) is equal to the power P in watts (W), times the luminous efficacy *η* in lumens per watt (lm/W).

*Φ*_{V(lm)} = *P*_{(W)} ×* η*_{(lm/W)}

So. The illuminance *E*_{v} in lux (lx) is equal to 10.76391 times the luminous flux *Φ*_{V} in lumens (lm) divided by the surface area *A* in square feet (ft^{2}).

*E*_{v(lx)} = 10.76391 ×* Φ*_{V(lm)} /* A*_{(ft}2_{)}

So the illuminance *E*_{v} in lux (lx) is equal to 10.76391 times the power P in watts (W), times the luminous efficacy *η* in lumens per watt (lm/W) divided by the surface area *A* in square feet (ft^{2}):

*E*_{v(lx)} = 10.76391 ×* P*_{(W)}* *×* η*_{(lm/W)}* */* A*_{(ft}2_{)}

So

lux = 10.76391 ×* *watts × (lumens per watt) / (square feet)

or

lx = 10.76391 ×* *W × (lm/W) / ft^{2}

What is the illuminance with power consumption of 30 watts, luminous efficacy of 25 lumens per watt and surface area of 200 square feet?

*Φ*_{V} = 10.76391 ×* *30 W × 25 lm/W / 200 ft^{2} = 40.36 lx

What is the illuminance with power consumption of 50 watts, luminous efficacy of 25 lumens per watt and surface area of 200 square feet?

*Φ*_{V} = 10.76391 ×* *50 W × 25 lm/W / 200 ft^{2} = 67.27 lx

What is the illuminance with power consumption of 100 watts, luminous efficacy of 25 lumens per watt and surface area of 200 square feet?

*Φ*_{V} = 10.76391 ×* *100 W × 25 lm/W / 200 ft^{2} = 134.54 lx

So The luminous flux *Φ*_{V} in lumens (lm) is equal to the power P in watts (W), times the luminous efficacy *η* in lumens per watt (lm/W).

*Φ*_{V(lm)} = *P*_{(W)}* *×* η*_{(lm/W)}

So The illuminance *E*_{v} in lux (lx) is equal to the luminous flux *Φ*_{V} in lumens (lm) divided by the surface area *A* in square meters (m^{2}).

*E*_{v(lx)} = *Φ*_{V(lm)} /* A*_{(m}2_{)}

So the illuminance *E*_{v} in lux (lx) is equal to the power P in watts (W), times the luminous efficacy *η* in lumens per watt (lm/W) divided by the surface area *A* in square meters (m^{2}).

*E*_{v(lx)} = *P*_{(W)}* *×* η*_{(lm/W)}* */* A*_{(m}2_{)}

So

lux = watts × (lumens per watt) / (square meters)

or

lx = W × (lm/W) / m^{2}

What is the illuminance with power consumption of 30 watts, luminous efficacy of 25 lumens per watt and surface area of 18 square meters?

*Φ*_{V} = 30 W × 25 lm/W / 18 m^{2} = 41 lx

What is the illuminance with power consumption of 50 watts, luminous efficacy of 25 lumens per watt and surface area of 18 square meters?

*Φ*_{V} = 50 W × 15 lm/W / 18 m^{2} = 69 lx

What is the illuminance with power consumption of 100 watts, luminous efficacy of 25 lumens per watt and surface area of 18 square meters?

*Φ*_{V} = 100 W × 25 lm/W / 18 m^{2} = 138 lx

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