Electric current in amps (A) to electric power in watts (W) calculator.
* Use e for scientific notation. E.g: 5e3, 4e-8, 1.45e12
So The power P in watts (W) is equal to the current I in amps (A), times the voltage V in volts (V).
P(W) = I(A) × V(V)
What is power consumption in watts when the current is 3A and the voltage supply is 120V?
Answer: the power P is equal to current of 3 amps times the voltage of 120 volts.
P = 3A × 120V = 360W
What is power consumption in watts when the current is 3A and the voltage supply is 130V?
Answer: the power P is equal to current of 3 amps times the voltage of 130 volts.
P = 3A × 130V = 390W
So The power P in watts (W) is equal to the power factor PF times the phase current I in amps (A), times the RMS voltage V in volts (V).
P(W) = PF × I(A) × V(V)
What is power consumption in watts when the power factor is 0.8 and the phase current is 3A and the RMS voltage supply is 120V?
Answer: the power P is equal to power factor of 0.8 times current of 3 amps times voltage of 120 volts.
P = 0.8 × 3A × 120V = 288W
What is power consumption in watts when the power factor is 0.8 and the phase current is 3A and the RMS voltage supply is 130V?
Answer: the power P is equal to power factor of 0.8 times current of 3 amps times voltage of 130 volts.
P = 0.8 × 3A × 130V = 312W
So The power P in watts (W) is equal to square root of [3] times the power factor PF times the phase current I in amps (A), times the line to line RMS voltage VL-L in volts (V).
P(W) = √3 × PF × I(A) × VL-L(V)
What is power consumption in watts when the power factor is 0.8 and the phase current is 3A and the RMS voltage supply is 120V?
Answer: the power P is equal to power factor of 0.8 times current of 3 amps times the voltage of 120 volts.
P = √3 × 0.8 × 3A × 120V = 498W
What is power consumption in watts when the power factor is 0.8 and the phase current is 3A and the RMS voltage supply is 130V?
Answer: the power P is equal to power factor of 0.8 times current of 3 amps times the voltage of 130 volts.
P = √3 × 0.8 × 3A × 130V = 540W
So The power P in watts (W) is equal to [3] times the power factor PF times the phase current I in amps (A), times the line to neutral RMS voltage VL-N in volts (V).
P(W) = 3 × PF × I(A) × VL-N(V)
Do not use typical power factor values for accurate calculations.
| Device | Typical power factor |
|---|---|
| Resistive load | 1 |
| Fluorescent lamp | 0.95 |
| Incandescent lamp | 1 |
| Induction motor full load | 0.85 |
| Induction motor no load | 0.35 |
| Resistive oven | 1 |
| Synchronous motor | 0.9 |
| Current (A) | Voltage (V) | Power (W) |
|---|---|---|
| 0.1 amps | 120 volts | 12 watts |
| 0.2 amps | 120 volts | 24 watts |
| 0.3 amps | 120 volts | 36 watts |
| 0.4 amps | 120 volts | 48 watts |
| 0.5 amps | 120 volts | 60 watts |
| 0.6 amps | 120 volts | 72 watts |
| 0.7 amps | 120 volts | 84 watts |
| 0.8 amps | 120 volts | 96 watts |
| 0.9 amps | 120 volts | 108 watts |
| 1 amps | 120 volts | 120 watts |
| 2 amps | 120 volts | 240 watts |
| 3 amps | 120 volts | 360 watts |
| 4 amps | 120 volts | 480 watts |
| 5 amps | 120 volts | 600 watts |
| 6 amps | 120 volts | 720 watts |
| 7 amps | 120 volts | 840 watts |
| 8 amps | 120 volts | 960 watts |
| 9 amps | 120 volts | 1080 watts |
| 10 amps | 120 volts | 1200 watts |
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